Underscore Equivalent Of _.pick For Arrays

I understand that pick is used to get back an object with only specified properties: _.pick({name: 'moe', age: 50, userid: 'moe1'}, 'name', 'age'); => {name: 'moe', age: 50} Ho

Solution 1:

You have to use _.map and apply the same _.pick on all the objects.

var data = [{name: 'moe1', age: 30, userid: 'moe1'},
            {name: 'moe2', age: 50, userid: 'moe1'},
            {name: 'moe3', age: 60, userid: 'moe1'}];

var result = _.map(data, function(currentObject) {
    return _.pick(currentObject, "name", "age");
});

console.log(result);

Output

[ { name:'moe1', age:50 },
  { name:'moe2', age:50 },
  { name:'moe3', age:50 } ]

If you want to get the objects in which the age is > 50, you might want to do, like this

var data = [{name: 'moe1', age: 30, userid: 'moe1'},
            {name: 'moe2', age: 50, userid: 'moe1'},
            {name: 'moe3', age: 60, userid: 'moe1'}];

functionfilterByAge(currentObject) {
    return currentObject.age && currentObject.age > 50;
}

functionomitUserId(currentObject) {
    return _.omit(currentObject, "userid");
}

var result = _.map(_.filter(data, filterByAge), omitUserId);    
console.log(result);

Output

[ { name: 'moe3', age: 60 } ]

You can do the same with chaining, as suggested by rightfold, like this

var result = _.chain(data).filter(filterByAge).map(omitUserId).value();